SQL Server 2008 "IDENTITY_INSERT Is ON" Error On Insert
Solution 1:
You need to explicitly mention column names in target table while inserting .
Replace Col1,Col2 etc with column list of CP.[dbo].[LOCALE_CODE] table
SET IDENTITY_INSERT CP.dbo.LOCALE_CODE ON
insert into CP.[dbo].[LOCALE_CODE] (Col1 ,Col2 , Col3)
select * from PP.dbo.LOCALE_CODE
You can use * in SELECT of source table PP.dbo.LOCALE_CODE
Solution 2:
There are basically 2 different ways to INSERT records without having an error:
1) When the IDENTITY_INSERT is set OFF. The PRIMARY KEY "ID" MUST NOT BE PRESENT
2) When the IDENTITY_INSERT is set ON. The PRIMARY KEY "ID" MUST BE PRESENT
As per the following example from the same Table created with an IDENTITY PRIMARY KEY:
CREATE TABLE [dbo].[Persons] (
ID INT IDENTITY(1,1) PRIMARY KEY,
LastName VARCHAR(40) NOT NULL,
FirstName VARCHAR(40)
);
1) In the first example, you can insert new records into the table without getting an error when the IDENTITY_INSERT is OFF. The PRIMARY KEY "ID" MUST NOT BE PRESENT from the "INSERT INTO" Statements and a unique ID value will be added automatically:. If the ID is present from the INSERT in this case, you will get the error "Cannot insert explicit value for identify column in table..."
SET IDENTITY_INSERT [dbo].[Persons] OFF;
INSERT INTO [dbo].[Persons] (FirstName,LastName)
VALUES ('JANE','DOE');
INSERT INTO Persons (FirstName,LastName)
VALUES ('JOE','BROWN');
OUTPUT of TABLE [dbo].[Persons] will be:
ID LastName FirstName
1 DOE Jane
2 BROWN JOE
2) In the Second example, you can insert new records into the table without getting an error when the IDENTITY_INSERT is ON. The PRIMARY KEY "ID" MUST BE PRESENT from the "INSERT INTO" Statements as long as the ID value does not already exist: If the ID is NOT present from the INSERT in this case, you will get the error "Explicit value must be specified for identity column table..."
SET IDENTITY_INSERT [dbo].[Persons] ON;
INSERT INTO [dbo].[Persons] (ID,FirstName,LastName)
VALUES (5,'JOHN','WHITE');
INSERT INTO [dbo].[Persons] (ID,FirstName,LastName)
VALUES (3,'JACK','BLACK');
OUTPUT of TABLE [dbo].[Persons] will be:
ID LastName FirstName
1 DOE Jane
2 BROWN JOE
3 BLACK JACK
5 WHITE JOHN
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